LeetCode Compare Version Numbers
来源：程序员人生 发布时间：2015-05-06 08:43:47 阅读次数：2500次
1.题目
Compare two version numbers version1 and version2.
If version1 > version2 return 1, if version1 < version2 return ⑴, otherwise return 0.
You may assume that the version strings are non-empty and contain only digits and the . character.
The . character does not represent a decimal point and is used to separate number sequences.
For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.
Here is an example of version numbers ordering:
0.1 < 1.1 < 1.2 < 13.37
2.解答
class Solution {
public:
vector<string> getAllVersionString(string version1){
vector<string> allVersion1;
string oneVersion1;
for(int i = 0; i < version1.size(); ++i){
if(version1[i] != '.'){
oneVersion1.push_back(version1[i]);
}else{
allVersion1.push_back(oneVersion1);
oneVersion1.clear();
}
}
allVersion1.push_back(oneVersion1);
return allVersion1;
}
int compareVer(vector<string> allVersion1, vector<string> allVersion2){
for(int i = 0; i < allVersion1.size(); ++i){
if(i < allVersion2.size()){
if(atoi(allVersion1[i].c_str()) < atoi(allVersion2[i].c_str())){
return ⑴;
}else if(atoi(allVersion1[i].c_str()) > atoi(allVersion2[i].c_str())){
return 1;
}
}else{
if(atoi(allVersion1[i].c_str()) > 0){
return 1;
}
}
}
return 0;
}
int compareVersion(string version1, string version2) {
vector<string> allVersion1 = getAllVersionString(version1);
vector<string> allVersion2 = getAllVersionString(version2);
int result = 0;
if(allVersion1.size() >= allVersion2.size()){
result = compareVer(allVersion1, allVersion2);
}else if(allVersion2.size() > allVersion1.size()){
result = -compareVer(allVersion2, allVersion1);
}
return result;
}
};
C++中好像没有分割的函数的，感觉我也写麻烦了。
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