一个根据列的范围分组汇总的Sql存储过程

1.需求说明

有如下表数据：

ID NUM
----------- -----------
1 2
2 3
3 2
4 2
5 12
6 2
7 1
8 5
9 1
10 1
11 1

输入分组参数,比如输入 "2,5,8,10" ,实现按 ID<=2,2<ID<=5,5<ID<=8,8<ID<=10,ID>10 分组查询，要得到下面的数据：

groupdata num
---------- -----------
id<=2 5
2<id<=5 16
5<id<=8 8
8<id<=10 2
id>10 1

2.存储过程如下：

--测试数据

create table TestData(ID int,NUM int)

insert TestData select 1,2

union all select 2,3

union all select 3,2

union all select 4,2

union all select 5,12

union all select 6,2

union all select 7,1

union all select 8,5

union all select 9,1

union all select 10,1

union all select 11,1

go



create proc spgroupcol

@numlist varchar(1000)

as

set nocount on

declare @t table(id int identity,groupdata varchar(10),a int,b int)

declare @i int,@pnum varchar(10),@j int

select @i=charindex(',',@numlist)

,@pnum=left(@numlist,@i-1)

insert @t select 'id<='+@pnum,null,@pnum



while @i>=1

begin

select @numlist=substring(@numlist,@i+1,len(@numlist)-@i)

select @j=charindex(',',@numlist) ;

if @i=@j

begin

insert @t select @pnum+'<id<='+substring(@numlist,0,@i),@pnum,substring(@numlist,0,@i)

select @pnum=left(@numlist,@i-1);

end

else

begin

insert @t select @pnum+'<id<='+substring(@numlist,0,@i+1),@pnum,substring(@numlist,0,@i+1)

select @pnum=left(@numlist,@i);

end

select @i=charindex(',',@numlist) ;

end



insert @t select 'id>'+@numlist,@numlist,null

select b.groupdata,num=sum(a.num)

from TestData a,@t b

where case

when b.a is null then case when a.id<=b.b then 1 else 0 end

when b.b is null then case when a.id>b.a then 1 else 0 end

else case when a.id>b.a and a.id<=b.b then 1 else 0 end

end=1

group by b.groupdata

order by min(b.id)

go



spgroupcol '2,5,8,10'

drop table TestData

sql存储过程的单步调试要在Vs2008中，服务器管理器中连接上数据库，找到存储过程右键单步调试。

转自：http://www.cnblogs.com/carysun/