删除C语言程序中所有的注释语句，代码实现
来源：程序员人生 发布时间：2015-01-19 09:05:54 阅读次数：2446次
原文链接：http://lixing123.com/archives/310
学习《C程序设计语言》到第1章最后，有1道题目：
编写1个删除C语言程序中所有的注释语句。要正确处理带引号的字符串与字符常量。在C语言中,注释不允许嵌套。
Exercise 1⑵3. Write a program to remove all comments from a C program. Don't forget to handle quoted strings and character constants properly. C comments don't nest.
刚开始，我用1种brute-force的方式，对每一个字符进行遍历，然落后行判断，有无进入注释。
这样做有1个非常麻烦的问题：只有连续检测到“//”或"/*"时，才肯定进入了注释状态；如果我们只检测到1个"/"，后面就是其它字符串的话，还得将这个单独的"/"打印出来。
而且有许多的分支状态，如果用if/else的话，会难以理解，并容易出错。
在网上搜了1下，发现有1种解法非常好：状态机。在各种状态之间跳转，逻辑清晰，不容易出错，出错了也容易调试。
下面把代码贴出来：
#include <stdio.h>
int state;
int c1,c2;
void change_state(int c);
int main(int argc, const char * argv[]) {
int c;
state = 0;
c1 = 0;
c2 = 0;
while ((c=getchar())!=EOF) {
c1 = c2;
c2 = c;
change_state(c);
}
if (/* DISABLES CODE */ (0)==1) {
printf("just test://abcd");
printf("just test:/*hello*/");
}
}
/*状态机函数*/
void change_state(int c){
if (state==0) {//普通状态
if (c=='/') {
state = 1;
}else if (c=='"'){
state = 5;
putchar(c);
}else if (c=='''){
state = 6;
putchar(c);
}
else{
state = 0;
putchar(c);
}
}else if (state==1) {//检测到1个'/'
if (c=='/') {
state = 2;
}else if (c=='*'){
state = 3;
}else{
state = 0;
putchar(c1);
putchar(c);
}
}else if (state==2) {// "//"注释状态
if (c=='
') {
state = 0;
putchar(c);
}else{
state = 2;
}
}else if (state==3) {// "/*"注释状态
if (c=='*') {
state = 4;
}else{
state = 3;
}
}else if (state==4) {
if (c=='/') {
state = 0;
}else{
state = 3;
}
}else if (state==5){//在"字符串里
if (c=='"') {
state = 0;
putchar(c);
}else if(c==''){
state = 7;
putchar(c);
}else{
state = 5;
putchar(c);
}
}else if (state==6){//在'字符里
if (c==''') {
state = 0;
putchar(c);
}else if(c==''){
state = 8;
putchar(c);
}else{
state = 6;
putchar(c);
}
}else if (state==7){//在"字符串里的""
state = 5;
putchar(c);
}else if (state==8){//在'字符串里的""
state = 6;
putchar(c);
}
}
以本段代码作为输入，结果以下：
#include <stdio.h>
int state;
int c1,c2;
void change_state(int c);
int main(int argc, const char * argv[]) {
int c;
state = 0;
c1 = 0;
c2 = 0;
while ((c=getchar())!=EOF) {
c1 = c2;
c2 = c;
change_state(c);
}
if ( (0)==1) {
printf("just test://abcd");
printf("just test:/*hello*/");
}
}
void change_state(int c){
if (state==0) {
if (c=='/') {
state = 1;
}else if (c=='"'){
state = 5;
putchar(c);
}else if (c=='''){
state = 6;
putchar(c);
}
else{
state = 0;
putchar(c);
}
}else if (state==1) {
if (c=='/') {
state = 2;
}else if (c=='*'){
state = 3;
}else{
state = 0;
putchar(c1);
putchar(c);
}
}else if (state==2) {
if (c=='
') {
state = 0;
putchar(c);
}else{
state = 2;
}
}else if (state==3) {
if (c=='*') {
state = 4;
}else{
state = 3;
}
}else if (state==4) {
if (c=='/') {
state = 0;
}else{
state = 3;
}
}else if (state==5){
if (c=='"') {
state = 0;
putchar(c);
}else if(c==''){
state = 7;
putchar(c);
}else{
state = 5;
putchar(c);
}
}else if (state==6){
if (c==''') {
state = 0;
putchar(c);
}else if(c==''){
state = 8;
putchar(c);
}else{
state = 6;
putchar(c);
}
}else if (state==7){
state = 5;
putchar(c);
}else if (state==8){
state = 6;
putchar(c);
}
perfect！
感谢@roma823 及其文章：http://blog.csdn.net/roma823/article/details/6364849
生活不易，码农辛苦
如果您觉得本网站对您的学习有所帮助,可以手机扫描二维码进行捐赠
